2x^2=4x-80

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Solution for 2x^2=4x-80 equation: 



2x^2=4x-80

We move all terms to the left:

2x^2-(4x-80)=0

We get rid of parentheses

2x^2-4x+80=0

a = 2; b = -4; c = +80;
Δ = b2-4ac
Δ = -42-4·2·80
Δ = -624
Delta is less than zero, so there is no solution for the equation

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